StringMap.opBinaryRight

Complexity: O(log(s)), where s is the number of the keys with the same length as the input key.

struct StringMap(T)

pure nothrow @nogc inout

inout(T)*

opBinaryRight

(

string op : "in"

)

(

scope const(char)[] key

)

Examples

StringMap!double map;
assert(("c" in map) is null);
map["c"] = 3.0;
assert(*("c" in map) == 3.0);